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206. 反转链表
给你单链表的头节点 head ,请你反转链表,并返回反转后的链表。
示例 1:
输入:head = [1,2,3,4,5]
输出:[5,4,3,2,1]
示例 2:
输入:head = [1,2]
输出:[2,1]
示例 3:
输入:head = []
输出:[]
提示:
链表中节点的数目范围是 [0, 5000]
-5000 <= Node.val <= 5000
- 来源:力扣(LeetCode)
- 链接:https://leetcode.cn/problems/reverse-linked-list
javascript
/**
* Definition for singly-linked list.
* function ListNode(val, next) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
*/
/**
* @param {ListNode} head
* @return {ListNode}
*/
// 解法一
var reverseList = function (head) {
if (!head || !head.next) return head
const last = reverseList(head.next)
head.next.next = head
head.next = null
return last
}
// 解法二
var reverseList = function (head) {
if (!head || !head.next) return head
const stack = []
let lst = new ListNode(),
last = lst
while (head) {
stack.push(head)
head = head.next
}
while (stack.length > 0) {
lst.next = stack.pop()
lst = lst.next
}
lst.next = null
return last.next
}
// test
function ListNode(val) {
this.val = val
this.next = null
}
var list = new ListNode(1)
var list1 = new ListNode(2)
var list2 = new ListNode(3)
var list3 = new ListNode(4)
var list4 = new ListNode(5)
list.next = list1
list1.next = list2
list2.next = list3
list3.next = list4
console.log(reverseList(list))